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Messages - wackojack

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1
IAC & Master Solvers Club / Re: 2024 MAY MSC
« on: March 31, 2024, 02:59:11 PM »
A: 5♣
Partner has forced to game with 3♠ and east has eschewed supporting ♠s in favour of bidding what looks like a non-forcing 4♦s.  This points to partner having ♠AKxx, or at least ♠Axxx.  Let’s give partner something like ♠AKxx, ♥QJ10xx, ♦xx, ♣Kx or maybe a singleton ♦ and one more ♣ or ♥.  If I pass, will partner cue again missing AK♥? No, it looks like I have to take the initiative and bid 5♣. I trust that partner will sign off in 5♥ with a doubleton ♦ and bid 5♦ with a singleton ♦.  Both of us (breaking the rules?) by bidding 2nd round controls😊 above the game level. 

B: 3NT
All I need for 3NT to be a good contract is for partner to have ♣KQxxx.  What about 6♣? If I put opps with 11 opposite 5, then partner has just 5 and most likely ♣KQ.  Suppose partner has 6♣s and a doubleton ♦?  Even then slam looks like it depends on clubs breaking 2-2.  So, I bid 3NT.

C: 2NT
Points good enough to make a game try so 2NT it is. 

D: 1♣
I will stick my neck out here and open 1♣.  This is risking zero in MSC.  Nevertheless, 2nd guessing what the experts might do in a quiz rather than what you (or they) would do at the table is unproductive.  The risk at the table, I believe, is less than the possible reward.  With 11 the hand is more likely than not to belong to us.

E: 2♠
2♠ looks right and better than double or pass

F: 4♦
I think that 4♦ gets the message over that I virtually have game in my hand and have longer clubs than hearts.

G: 4♦
4♦ The LAW.  Opps have got the balance of points (unless partner makes gross 2♦ openings) Give partner 3 spades then total tricks = 19 and so 5♦ is a phantom. Defending 4♠ I don’t see that a heart lead would be crucial. 

H: A♠
I am lost.  Let’s try A♠

2
IAC & Master Solvers Club / Re: 2024 APRIL MSC
« on: February 29, 2024, 10:52:58 PM »
SOLUTIONS FOR:
jack Goody
England

PROBLEM A: 3 Diamonds
PROBLEM B: Double
PROBLEM C: 5 Notrump
PROBLEM D: 3 Notrump
PROBLEM E: 3 Hearts
PROBLEM F: 6 Notrump
PROBLEM G: Double
PROBLEM H: Heart Jack

3
IAC & Master Solvers Club / Re: 2024 APRIL MSC
« on: February 29, 2024, 06:13:02 PM »
A:  3 !D
Partner could have something like ♠Jx, ♥ Ax, ♦AKxx, ♣AKxxxx where we want to be in 5♦.  Or partner could have 18+ with just long clubs.  Partner must have a doubleton ♠ simply because if opps had a 9 card fit they surely would have raised spades.  Could it be ♠Jx or a low doubleton?  I think 3♦ would cover all bases. Maybe partner would next bid 3♠ with ♠Jx looking for 3NT, or raise diamonds with ♦AKxx, or just repeat clubs with just long clubs. 

B: 5NT
2 places to play. The only bid that gets anywhere near describing my hand.

C:
Double
We have a good chance of making 3+ tricks here.

D: 1 !D
A 1♦ overcall should be on 5 good diamonds and an opening bid.  So I go for 3N.

E: 3 !H
This is a gamble on partner having 5 hearts or at least J10xx

F: 6NT
Give partner a min opener ♠AQxxx, ♥Axxx, ♦xx, ♣ Jx  and we have 12 tricks in clubs or no trumps. I trust that 3♠ is forcing but I want to either play in no trumps or clubs to protect my K♦.  So 3♠ gets me nowhere.  I am not selling out with 3NT.  We could just about be missing 2 aces partner having ♠AQJxx, ♥QJxx, ♦Qx, ♣xx so I cannot blast 6NT. 
Is there a way out?  If I bid 4NT, that would (I assume ) be keycard in ♥s so that is out. 
What about 4♣?  I don’t think that will get me anywhere.  In principle I will bid what I would bid at the table and not what I think the panel will bid.  So 6NT it is.

G: Double
Awkward if partner has say ♠xx, ♥KQx, ♦AKxx, xxxx.  Say you double.  Partner would likely bid 2♣ and then you would have to correct to 2♥ non forcing.  Lots could go wrong but double is the least of evils.

H:  J !H
WTP?   



4
IAC & Master Solvers Club / Re: 2024 MARCH MSC
« on: January 31, 2024, 08:27:41 PM »
SOLUTIONS FOR:
Jack Goody
England

All my comments were lost and I have no time left  :-[

PROBLEM A: 3 Diamonds
PROBLEM B: Double
PROBLEM C: 1 Notrump
PROBLEM D: 2 Hearts
PROBLEM E: Double
PROBLEM F: 2 Clubs
PROBLEM G: 1 Heart
PROBLEM H: Heart 5

5
IAC & Master Solvers Club / Re: 2024 MARCH MSC
« on: January 31, 2024, 08:08:21 PM »
A: 3 !D
B: Dbl
C 1NT
D: 2 !H
E: Dbl
F: 2 !C
G: 1 !H
H: 2 !H

6
IAC & Master Solvers Club / Re: 2023 September MSC
« on: July 31, 2023, 11:10:09 AM »
SOLUTIONS FOR:
Jack Goody
U.K.

PROBLEM A: 3 Notrump
PROBLEM B: 3 Spades
PROBLEM C: 4 Clubs
PROBLEM D: 3 Hearts
PROBLEM E: Pass
PROBLEM F: 3 Spades
PROBLEM G: Double
PROBLEM H: Spade 4

7
IAC & Master Solvers Club / Re: 2023 September MSC
« on: July 31, 2023, 11:04:07 AM »
A: 3NT
Partner's 3 !D 4th suit bid says "tell me more".  I have extras but not enough for a slam try so 3NT it is.

B: 3 !S
BWS says that a double jump shift is a splinter. So if I splinter with 3 !S partner is obliged to cue a minor then I will bid 4 !S (exclusion)

C: 4 !C
Slam cannot be ruled out. Partner could have  !S xxxxx,  !H Kx,  !D Kx,  !C AKxx where 7  !C is almost a laydown.  So I will force with 4 !C

D: 3 !H
Partner has a likely balanced 3-4-3-3.  I will be cautious and bid a non-forcing 3 !H.

E:  Pass
We have a likely 8 card spade fit and the opps a likely 9 card heart fit.  If the opps can make 4 !H, then we will only make 7 tricks in spades.  A disaster sac.  If the opps can only make 3 !H, then we will be 1 off in 3 !S.  (A good sac) To cater for this we must pass and then pass ff opps bid 4 !H or bid 3 !S if the opps pass over 3 !H.   

F: 3 !S
If we have 2 spade losers and play in 5 !D, we need partner to have A !C and at least a doubleton diamond.  If partner has a stop in spades we have a better chance in 3NT.

G: Double
I am not sure about this.  Perhaps a 3 !S splinter is better. If opps raise to 4 !S partner will not know that I have a spade void.  OTOH a 3 !S splinter could reveal too much to the opps or it could be what partner needs to know to find the right spot.

H: 4 !S
What lead is (a) least likley to give a trick and (b) is the most attacking?  I just don't know.  I will be different and go for the 4 !S.

8
IAC & Master Solvers Club / Re: 2023 JULY MSC
« on: May 29, 2023, 10:19:23 PM »

SOLUTIONS FOR:
Jack Goody
U.K.

These bids are what I would do at the table against expert opponents.  No way will I try and 2nd guess what I think the panel will do and go against my judgement on what I think is right.   
PROBLEM A: 4 Notrump
PROBLEM B: 2 Notrump
PROBLEM C: 3 Spades
PROBLEM D: Pass
PROBLEM E: Double
PROBLEM F: 3 Notrump
PROBLEM G: 3 Hearts
PROBLEM H: Club 6

9
IAC & Master Solvers Club / Re: 2023 JULY MSC
« on: May 21, 2023, 08:13:54 PM »
Problem A

4NT. 
I would like to ask partner how many Aces.  If 2 then I ask for kings.  How do I do that? I think 4NT must be asking for aces.  So 4NT.

Problem B

2NT.
I have a balanced 13 so I must show that by bidding 2NT.  OK what could go wrong?
Suppose partner had ♠x,  ♥AQx, ♦Qxx, ♣KQJxxx.  Then I would expect him to bid 3♣ and we get to the reasonable 5♣ contract.
Suppose partner had ♠Jx, ♥Axx, ♦Qxx, ♣KQJxx and you raise to 3♣. Then only poor bidding will get you to the making 3NT.  So 2NT it is. 

Problem C
3♠
First of all, after 1♥-2♣, I believe that if you rebid 2♥ in this position, then you are showing a 6 card ♥ suit. You have good alternatives with only a 5 card ♥ suit.   With say ♠xx, ♥KQJ10x, ♦Axx, ♣Kxx,; then you  would raise to 3♣.  With say ♠Qxx, ♥KQJ10x, ♦Ax, ♣Jxx you would rebid 2NT (similar to problem B) So when partner bids 3♦, he has longer clubs than diamonds and not 4♠ and likely singleton ♥.  So 3145, 2146  or perhaps even wilder.  So I bid the 4th suit 3♠ and partner will bid 3N with 3145 and a partial ♠ guard. Or 4♣ with 2146.   If I bid 3♠ now partner should be able to supply the answers.
Partner with a strong hand say: ♠Ax, ♥ x, ♦ KQJ10, ♣ AKQxxx will bid 4NT

Problem D
Pass 
Partner has likely 1444 distribution, say ♠ x, ♥ KJxx, ♦ Axxx, ♣ AQxx.  If as good as this we will take 2♠ + likely 3♥, +2♦ + 1♣ = +500 more than game our way.  If less then we will still get more than the possible  part score.


Problem E
Double:
We could only have an 8 card fit.  Partner could have a 3244 distribution; say ♠Qxx, ♥xx, ♦Qxx, ♣Kxxx.  If I double could we still get to 4♥?  I think so.  Partner will bid 3♣ and I will rebid 3♥.   And partner will raise to 4♥ with a doubleton.  I note that opps having a 10 card ♠ fit and we having an 8 card ♣ or ♥ fit then total tricks = 10.  So if we can make 4♥ then opps should go 2 off in 4♠ and so we have a 500 penalty which is more than our nv +420 in 4♥ . 


Problem F
3NT
First thoughts were that I am too strong to bid 3NT. Say partner has ♠ AKQ10xx, ♥ Kxx, ♦x, ♣ AKQ.  Then would we miss the ♣ or ♠ slam?  OTOH this is match point pairs and perhaps we should go for the certain 3NT +1 or +2. 
 
 

Problem G
3♥
I think shows the minors.  Problem:  What if partner then bids 3♠? I think I will bid 3NT and hold my breath.


Problem H

Why did East double and then bid 2 suits when a response of 2♠ would have been forcing? I will leave this until I can answer that question.   

10
IAC & Master Solvers Club / Re: 2023 JUNE MSC
« on: April 09, 2023, 08:59:46 AM »
Yes, a nasty problem.

Optimistically:   
West opened with 12 East has 3.  So partner has 6. Maybe:   !S Axx.  !H Qxxxx,  !D xx,  !C xxx. That just about makes 4 !H a good contract.  BUt only just.

Pessimistically:
West opened with 15, East has 3.  So partner has 3.  Maybe:  !S xxx  !H Qxxxx,  !D Jx,  !C xxx.   You lose 5 tricks off the top.

So at match points it is tempting to pass. 


11
Sleight of Hand / Re: How to bid to 3NT?
« on: March 30, 2023, 10:50:39 AM »
I remember this hand and gave my opening bid a lot of thought.  Open 1NT or 1H?
Open 1NT
Advantages:
It is has 15HCP and is worth 16 and so gets over my strength
It right sides the contract ensuring that I am declarer.  eg   !C Q7 is best led up to esp if partner has Axx. 
Disadvantages:
If partner has 4 spades and fewer than 8HCP then I miss the 4-4 spade fit.
Open 1 !H
Advantages:
I will always find a 4-4 spade fit or a 5-3  !H fit if there is one.
Disadvantages: If partner has 9-10 HCP I am unlikely to find a 3NT contract. 

I decided to open 1 !H and my robot responded 1NT.  This gave me a problem.  Normally I would only pass 1NT if I had 12HCP trusting that partner had a hand worth fewer than 13.  On this occasion though I decided to pass hoping that partner did not have a hand worth 10HCP (partner had already passed)  Also robots do not shout at you if your decision does not turn out well.

As far I remember this was the final contract and my robot partner mad 9 tricks.

I think this was a MP tourney.  Maybe at imps I would go in favour of a 1NT opening bid. 


 


12
IAC & Master Solvers Club / Re: 2023 APRIL MSC
« on: March 01, 2023, 04:58:51 PM »
SOLUTIONS FOR:
Jack Goody

Guildford
England

PROBLEM A: 3 Diamonds  Reckon just good enough to bid 3N at imps.  However, at MP just 3D
PROBLEM B: 3 Spades      That tells partner game interest
PROBLEM C: 1 Notrump    That is what I have
PROBLEM D: 2 Spades      No other bid       
PROBLEM E: 2 Clubs         Considered 2N and rejected it. 
PROBLEM F: 1 Spade        It will not be passed out
PROBLEM G: 3 Hearts       Control agreeing diamonds.  It cannot be natural support
PROBLEM H: Spade 10      Looks like it gives away least

13
IAC & Master Solvers Club / Re: 2023 MARCH MSC
« on: January 31, 2023, 11:46:21 PM »
SOLUTIONS FOR:
Jack Goody
Guildford
England

PROBLEM A: Pass
PROBLEM B: 3 Diamonds
PROBLEM C: 3 Hearts
PROBLEM D: 1 Notrump
PROBLEM E: 4 Spades
PROBLEM F: 6 Hearts
PROBLEM G: 3 Clubs
PROBLEM H: Spade 2

14
IAC & Master Solvers Club / Re: 2023 MARCH MSC
« on: January 31, 2023, 11:38:40 PM »
A: Pass
We need 6 tricks if I pass for penalties.  Give partner only 11 points say ♠Kxx, ♥Axx ♦x ♣Axxxxx and I can see 3 tricks in ♦s (2+ruff) + 2 likely ♠+ 1♥ +1♣ and we get +200. I think we would have to be very unlucky for 2♣ to make. 

B: 3 !D
Give partner ♠ Axx, ♥ 10xxx, ♦ Kxx, ♣QJx, then game in ♠ is likely.  So if our agreement is that 2♠ is the weakest action, then we must find an alternative. So lets try 3♦ and see if partner can help us there.   

C: 3 !H
I must show support immediately. So a forcing 3♥? 4♦ splinter?  Or even 5♦ splinter? I think the most economical bid allowing partner to express her hand more.
3 !H

D: 1NT
I just bid my hand. 1NT

E: 4 !S
Cheapest bid with likely misfit.  4 !S

F: 6 !H
Since I have a void in spades, I imagine that partner likely has a balanced 12-14 with 3 hearts.  Say ♠Axxx, ♥Qxx, ♦ KJxx, ♣ Kx where 6 !H looks good.  Shall I try 5 !H or 6 !H? OK lets go the whole hog and bid 6 !H.

G: 3 !C
How can I know if partner has useless high spades or very useful high diamonds? Best try 3♣ and see if partner bids 3♦.  If so then we are slamming.

H: 2 !S
Speculative 2 !S

15
IAC & Master Solvers Club / Re: 2023 February MSC
« on: December 31, 2022, 03:45:21 PM »
SOLUTIONS FOR:
Jack Goody
Guildford
U.K.

PROBLEM A: Double
PROBLEM B: 3 Hearts
PROBLEM C: 3 Notrump
PROBLEM D: 2 Spades
PROBLEM E: 2 Notrump
PROBLEM F: 3 Spades
PROBLEM G: 1 Heart
PROBLEM H: Diamond 10

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