I took "rebid" to mean after the nmf.
I confess I did not think about it all that much.
I gather that was the intended meaning.
There is some interplay between this and the issue of 1m-1
-? when opener holds four spades.
If partner bids 1NT over 1
while holding four spades we will never, hardly ever, be finding that spade fit, if there is one. Say I'm responded, holding 4=4=3=2. Partner opens 1m, I respond 1
, partner bids 1NT. Often I lack the strength to bid at the 2 level so we are playing 1NT. If partner skipped over his four card spade suit, well, we miss the spade fit. And, if I have an 11 count with four spades then after 1m-1
-1NT I invite by bidding 2NT after 1
- 1
- 1NT.
I suppose that with 4=4=3=2 we could play that 2 of the other minor over 1m-1
- 1NT is checking back for a spade fit. I don't think of it as a standard part of nmf, and I would need at least invit values to use it.
Anyway, I am taking the topic to be: If the auction begins 1m-1
-1NT -nmf, then what happens next if opener holds four hearts and three spades.
The view I was presenting is that if opener, after 1m-1
- 1NT nmf, first shows hearts when holding both four hearts and three spades. Then, if responder has four hearts he shouts whoopee and we play in hearts. If responder, as most often happens, has five spades but does not have four hearts, then, after the 2
response to the nmf call, he can rebid a passable 2
with a minimum, or bid 2NT, or 3NT with five spades and a non-minimum.
I imagine nmf can be adapted to partnerships for which opener regularly bids 1NT over responder's 1
, even when holding four spades. There is no way around the fact that if responder is 4-4 in the majors and has an 8 count, he will pass after 1m-1
- 1NT.